x=-4x^2+104x+0

Solution for x=-4x^2+104x+0 equation:

x=-4x^2+104x+0

We move all terms to the left:

x-(-4x^2+104x+0)=0

We get rid of parentheses

4x^2-104x+x-0=0

We add all the numbers together, and all the variables

4x^2-103x=0

a = 4; b = -103; c = 0;
Δ = b2-4ac
Δ = -1032-4·4·0
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10609}=103$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-103)-103}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-103)+103}{2*4}=\frac{206}{8}
=25+3/4
$